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mcouil9369
19.12.2019 •
Physics
A960-kg sports car collides into the rear end of a 2300-kg suv stopped at a red light. the bumpers lock, the brakes are locked, and the two cars skid forward 2.6 m before stopping. the police officer, estimating the coefficient of kinetic friction between tires and road to be 0.80, calculates the speed of the sports car at impact. what was that speed? express answer in two significant figures.
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Ответ:
the speed of the sports car at impact= 21.66 m/s
Explanation:
maximum Acceleration of the car moving on a rough road is given by
= -μg= 0.8×9.81= -7.848 m/s^2
if v is the initial velocity Let vf be the velocity of car after collision and d=2.6 m be the displacement of the car after collision
we know that
⇒![(v_f)^2-0^2= 2\times7.848\times2.6](/tpl/images/0425/6633/94f72.png)
v_f= 6.38 m/s
now using the law of conservation of momentum before and after collision
we have
v_{isuv}= 0 m/s
v_{ic} =21.66 m/s
the speed of the sports car at impact= 21.66 m/s
Ответ:
speed of car is 21.6 m/s
Explanation:
Given speed:
sport car weight is 960 kg
SUV car weight is 2300 kg
skid distance is 2.6 m
coefficient of friction is 0.80
Taking After impact:
force of kinetic friction = µk = µ(m1 +m2) g
F = (0.80)(960+2400)(9.81) = 25,584.48 N
acceleration![a = \frac{F}{M} = \frac{25584.48}{(960+2300)}](/tpl/images/0425/6633/66636.png)
a = 7.84 m/s^2
from equation of motion
d =1/2 at^2
siolving for t
t = 0.813 s
momentum after collision MV
mometum of car before collision = MV = 20778.97 KGM.S
Speed of car before collision =![v = \frac{m}{M1} = \frac{20778.97}{960} = 21.64 m/s](/tpl/images/0425/6633/65b9f.png)
Ответ:
Hey
First, you need to know that radiation is vital for life on earth and the process of photosynthesis. also, you couldn't see without radiation.
But some radiation is harmful to DNA such as x-rays and gamma rays. and most of the energy is lost to radiation (created by heat, fission, and fusion).