Aball having a mass of 0.20 kilograms is placed at a height of 3.25 meters. if it is dropped from this height, what will be the kinetic energy of the ball when it reaches 1.5 meters above the ground?

Initially the total energy of the object, which is only PE.

PE = mgh = 0.2kg * 10m/s² * 3.25m = 6.5 J

When it is at 1.5m above the ground, it has both Kinetic and Potential Energy.

At 1.5m above the ground:
PE = mgh = 0.2kg * 10m/s² * 1.5m = 3 J

But at such mid level, PE + KE 

PE + KE = Total (Conserved) 

3 + KE = 6.5

KE = 6.5 - 3 = 3.5

Kinetic energy at 1.5 above ground = 3.5 J

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Step-by-step explanation: