Physics: Abasketball player throws the ball at a 47 angle above the horizontal to a hoop which is located a horizontal distance l = 5.0 from the point of release and at a height h = 0.8 above it. what is the required speed if the basketball is to reach the hoop?

Abasketball player throws the ball at a 47 angle

jonlandis6

13.01.2022

v_0 = 1.71

Explanation:

the parabolic movment is described by the following equation:

$y = tan(a)x-\frac{1}{2v_0^2(cos(a))^2}gx^2$

where y is the height of the ball, a is the angle of launch, v_0 the initial velocity, g the gravity and x is the horizontal distance of the ball.

So, if we want that the ball reach the hood, we will replace values on the equation as:

$0.8 = tan(47)(5)-\frac{1}{2v_0^2(cos(47))^2}(9.8)(5)^2$

Finally, solving for v_0 , we get:

$v_0=\sqrt{\frac{-9.8(5)^2}{(0.8-tan(47)(5))2cos^2(47)}}$

v_0 = 1.71

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hewonabi123

16.05.2020

Explanation:

Fixed pulley consists of a wheel fixed to a shaft and is used in conjunction with a belt to transfer energy to another fixed pulley.

It rotates about its central axis but does not move vertically or horizontally.

A movable pulley consists of a shell, a movable wheel and a rope.

Movable pulleys are also know as block and tackle.

It rotates and moves vertically and horizontally.

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