Acar drives 40 miles east, turns around, then drives 30 miles west. (a) find the distance traveled by the car. (b) find the car’s displacement.

Part A)

Distance is given as sum of total path length

So here as we are given that car drives 40 miles East and 30 miles West

So here the total path length is

Part B)

Displacement is given as straight line distance between initial and final position

So here we can see that

East

West

Now the total displacement will be

so the displacement will be 10 miles East

F=kq1q2/r2

"F" is the resulting force between the two charges. The distance between the two charges is "r." The "r" actually stands for "radius of separation" but you just need to know it is a distance. The "q1" and "q2" are values for the amount of charge in each of the particles.

Explanation: