Acar traveling at 40m/s starts to decelerate steadily. it comes to a complete stop in 12 seconds. what is the acceleration?

Velocity - v =0 m/s,

initial velocity - v(0)= 40 m/s

a - acceleration,

time - t = 12 s.

v=v(0) - at

0 = 40m/s - a*12s

12a = 40

a = 3.3 m/s²

28.8m

Explanation:

Given parameters:

Time of fall  = 2.4s

Acceleration due to gravity = 10m/s²

Unknown:

Height of cliff  = ?

Solution:

To solve this problem, we use the expression:

          H  = ut + gt²  

u is the initial velocity

t is the time taken

g is the acceleration

t is the time

      H  = 0x2.4  + x 10x2.4²   = 28.8m