Acar traveling at 7.3 m/s accelerates at the rate of 0.82 m/s2 for an interval of 7.4 s. find vf.

Explanation:

We have equation of motion v = u + at

     Initial velocity, u = 7.3 m/s

     Final velocity, v = ?

     Time, t = 7.4 s

     Acceleration,a = 0.82 m/s²

     Substituting

                      v = u + at  

                      v = 7.3 + 0.82 x 7.4

                      v = 13.368 m/s

Final velocity is 13.37 m/s

answers:

m2 = 1.05 kg and m1 = 4.75 kg

Explanation:

the gravitational force is given by:

             Fg = Gm1×m2/(r^2)

9.20×10^-9 = [(6.67×10^-11)×(m1×m2)]/[(19×10-2)^2]

    (m1×m2) = 4.98 kg^2

             m1 = 4.98/m2 kg

but we given that:

m1 + m2 = 5.80 kg

4.98/m2 + m2 = 5.80

4.98 + (m2)^2 = 5.80×m2

(m2)^2 - 5.80×m2 + 4.98 = 0

by solving the quadratic equation above:

m2 = 4.75 kg or m2 = 1.05 kg

due to that from the information, m2 has a lighter mass, then m2 = 1.05 kg.

then m1 = 5.80 - 1.05 = 4.75 kg.