Acell has an internal resistance of 0.02ohms and e.m.f of 2.0v calculate it's terminal p.d if it's delivers (a)5a ( b)50a

(a) The terminal voltage of the cell is 1.9 V.

(b) The terminal voltage of the cell is 1.0 V.

Explanation:

Given:

(a)

E.M.F of the cell (E) = 2.0 V

Internal resistance of the cell (r) = 0.02 ohms

Current passing through the cell (I) = 5 A

Now, the potential difference across the terminals of the cell is given as:

Plug in the given values and solve for 'V'. This gives,

Therefore, the terminal voltage of the cell is 1.9 V.

(b)

E.M.F of the cell (E) = 2.0 V

Internal resistance of the cell (r) = 0.02 ohms

Current passing through the cell (I) = 50 A

Now, the potential difference across the terminals of the cell is given as:

Plug in the given values and solve for 'V'. This gives,

Therefore, the terminal voltage of the cell is 1.0 V.

The answer is b