Acertain car is capable of accelerating at a rate of 0.60 m/s^2. how long does it take for this car to go from a speed of 55mi/h to a speed of 60 mi/h?
i know the answer is 3.7seconds! i am just confused on the steps to get the answer.

This car needs 3.7 seconds to go from a speed of 55 mi/h to a speed of 60 mi/h.

Acceleration is rate of change of velocity.

a = acceleration ( m/s² )

v = final velocity ( m/s )

u = initial velocity ( m/s )

t = time taken ( s )

d = distance ( m )

Let us now tackle the problem !

Given:

Acceleration = a = 0.60 m/s²

Initial Velocity = u = 55 mi/h = 24,5872 m/s

Final Velocity = v = 60 mi/h = 26,8224 m/s

Unknown:

Time Taken = t = ?

Solution:

Recall the formula for calculating acceleration as mentioned above.

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate

Newtons II law:

    It  is defined as "the net force acting on the object is a product of mass and acceleration of the body" . Also it defines that the "acceleration of an object is dependent on net force and mass of the body".

Let us assume that,a string is attached to the cart, which passes over a pulley along the track. At another end of the string a weight is attached which hangs over the pulley. The hanging weight provides tension in the spring, and it helps in accelerating the cart. We assume that the string is massless and no friction between pulley and the string.

Whenever the hanging weight moves downwards, the cart will accelerate to right side.

For the hanging weight/mass

When hanging weight of mass is m₁ and accelerate due to gravitational force g.

           Therefore we can write F = m₁ .g

and the tension acts in upward direction T (negetive)

        Now, Fnet = m₁ .g - T

                          = m₁.a

So From Newtons II law F =  m.a