Physics: Achild is holding a ball with a diameter of 5.70 cm and average density of 0.0835 g/cm3 under water. determine the force (in n) needed to hold it completely submerged.

Achild is holding a ball with a diameter of 5.70

sjjarvis4806

11.01.2022

0.488 N

Explanation:

Given , The ball has diameter (d)=5.70 cm = 0.0570 m

radius(r) = d/2 = 2.85 cm = 0.0285 m

Average density =0.0835g/cm^3 = 83.5 kg/m^3

There are two forces acting on the ball.. i.e. The buoyancy force and weight of the ball.

The force required to completely submerged under water= Buoyancy force - Weight of ball

buoyancy force = volume×density of water×g

$=\frac{4}{3} \pi r^{3}dg$

$=4.18\times(0.0285)^3\times1000\times9.8$ [ density of water = 1000 kg/m3]

=0.532 N

mass of ball = average density×Volume

$=83.5\times4.18\times(0.0285)^3$

= 0.004529 kg

Weight of ball = mg = 0.004529×9.81 =0.044 N

Required force = 0.532 - 0.044 = 0.488 N.

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darkghostmist

21.02.2022

The graph shows direct proportion because it is a straight line

through the origin.

Explanation:

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