wrivera32802
21.11.2019 •
Physics
Acircular loop of wire with area a lies in the xy-plane. as viewed along the z-axis looking in the −z direction toward the origin, a current i is circulating clockwise around the loop. the torque produced by an external magnetic field b is given by τ =d(3i^−4j^), where d is a positive constant, and for this orientation of the loop the magnetic potential energy u=−μ .b is negative. the magnitude of the magnetic field is b0=15d/ia.
determine the vector magnetic moment of the current loop. express your answer in terms of the variables i^a, a^a, i^i, j^j and k^k.
(a)-determine the component bx of b
(b)-determine the component by of b
(c)-determine the component bz of b
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Ответ:
Explanation:
Given:
Charge = q
Electric field strength =
weight of the droplet = mg
The charge is suspended motionless. This is because the electric force on the charge is balanced by the weight of the droplet.
electric force on charged droplet,
This is balanced by the weight,
Equating the two: