Acurrent-carrying wire passes through a region of space that has a uniform magnetic field of 0.92 t. if the wire has a length of 2.6 m and a mass of 0.60 kg, determine the minimum current needed to levitate the wire. a

Current, I = 2.45 T

Explanation:

It is given that,

Magnetic field, B = 0.92 T

Length of wire, l = 2.6 m

Mass, m = 0.6 kg

We need to find the minimum current needed to levitate the wire. It is given by balancing its weight to the magnetic force i.e.

I = 2.45 A

So, the minimum current to levitate the wire is 2.45 T. Hence, this is the required solution.

option B is the correct option

Explanation:

According to momentum conversion,

momentum of one car= 6600×2=13,200kgm/s

momentum of another car=5,400×(-3)=16,200kgm/s

Then,

Momentum of second car-momentum of first car

=16,200-13200

=3000kgm/s

mass of first car -mass of second car

=6600-5400

=600kg

final velocity=3000/600=2.5 m/s