Acurrent of 0.96 amps flows through a copper wire 0.44 mm in diameter when connected to a potential difference of 15 v. how long is the wire?

The length of the copper wire, which flows the current of 0.96 amps at a potential difference of 15 v is 141.1 meters.

What is Ohm's law?

Ohm's law states that for a flowing current, the potential difference of the circuit is directly proportional to the current flowing in it. Thus,

Here, (V) is the potential difference, and (I)is the current.

It can be written as,

Here, (R) is the resistance of the circuit.

The current of 0.96 amps flows through a copper wire when connected to a potential difference of 15 v. Thus, by using the above formula of ohm's law, the resistance of the wire can be found out as,

Now, the resistance of a metal wire can be given as,

Here, () is the resistivity of a wire (L) is the length of a wire, and A is the cross-sectional area of it.

As the resistivity of a copper wire is and the diameter of the wire is 0.44 mm. Thus, put the values in the above formula as,

Thus, the length of the copper wire, which flows the current of 0.96 amps at a potential difference of 15 v is 141.1 meters.

Learn more about Ohm's law here;

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By using Ohm's law, we can calculate the resistance of the wire. Ohm's law states that:

where V is the potential difference across the conductor, I is the current and R the resistance. Rearranging the equation, we get


Now we can use the following equation to calculate the length of the wire:
(1)
where
is the resistivity of the material
L is the length of the conductor
A is its cross-sectional area
In this problem, we have a wire of copper, with resistivity . The radius of the wire is half the diameter:

And the cross-sectional area is


So now we can rearrange eq.(1) to calculate the length of the wire:

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