Acurve in a road forms part of a horizontal circle. as a car goes around it at constant speed 14.0 m/s, the total force exerted on the driver has magnitude 110 n. what are the magnitude and direction of the total vector force exerted on the driver if the speed is 24.0 m/s instead?

Answer;

= 323.27 N

Explanation;

F is proportional to v^2  

F2/F1 = (v2/v1)^2

= (24.0/14)^2  

F2 = 110*(24.0/14)^2

= 323.27 N

Explanation:

Friction is the drive between an object in motion and the surface on which it moves. Friction is the outside constrain that acts on objects and causes them to moderate down when no other outside drive acts upon them.