Adump truck accelerates uniformly from a resting position to a velocity of 35 m/s north in 20 seconds. what is the displacement?

a.) 1.75 m north
b.) 61.25 m north
c.) 350 m north
d.) 700 m north

As this is a straight-line motion problem, the following formulas will be used to solve for acceleration, which is used to solve for displacement:

Vf = Vi + a * t
s = Vi * t  + 1/2 (a*t^2)

Where: Vf = final velocity
Vi = initial velocity
a = acceleration
t = time
s = displacement

Using eq.1 :

35 m/s = 0 m/s + a * 20 s
a = 35 / 20
a = 1.75 m/s^2

Using eq.2:

s = 0 * 20 + 1/2 (1.75 * 20^2)
s = 350 m

Therefore, the correct answer is C.

Is it possible to show the graph?