rajene9302
14.07.2019 •
Physics
Aforce of 1.5 × 102 n is exerted on a charge of 1.4 × 10–7 c that is traveling at an angle of 75° to a magnetic field. if the charge is moving at 1.3 × 106 m/s, what is the magnetic field strength? 8.2 × 102 t 8.5 × 102 t 3.2 × 103 t 6.4 × 1010 t
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Ответ:
Option (B) is correct.The magnetic field strength=8.5 x 10² T
Explanation:
the magnetic force Fm is given by
Fm= q V B sinθ
q= charge=1.4 x 10⁻⁷ C
v= velocity= 1.3 x 10⁶ m/s
B= magnetic field strength
Fm= magnetic force= 1.5 x 10² N
θ=75°
so 1.5 x 10²=(1.4 x 10⁻⁷) (1.3 x 10⁶ ) (B) sin75
B=8.5 x 10² T
Ответ:
B
Explanation:
Ответ: