gshreya2005
12.07.2019 •
Physics
Aforce of 18 lb is required to hold a spring stretched 8 in. beyond its natural length. how much work w is done in stretching it from its natural length to 11 in. beyond its natural length? w = ft-lb
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Ответ:
11.54 ft - lb
Explanation:
F = 18 lb, x = 8 in = 8 / 12 = 0.66 ft
F = k x
k = F / x = 18 / 0.66 = 27.27 lb/ft
y = 11 in = 11 / 12 ft = 0.92 ft
Work done = 1 /2 x k x y^2
W = 0.5 x 27.27 x 0.92 x 0.92 = 11.54 ft - lb
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