Ahome run just clears a fence 105 m from home plate. the fence is 4.00 m higher than the height at which the batter struck the ball, and the ball left the bat at a 31.0° angle above the horizontal. at what speed did the ball leave the bat?
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Ответ:
u= 35.30 s
Explanation:
given,
horizontal distance covered by the ball = 105 m
vertical distance to clear by the ball = 4 m
angle at which the ball was hit = 31°
Let the initial velocity is u m/s and the ball take t sec to reach the fence.
ut = 122.5
Using
t = 3.47 s
now,
u= 35.30 s
Speed of the ball when it leaves the bat u= 35.30 s
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