Physics: Alawyer drives from her home, located 1 mile east and 8 miles north of the town courthouse, to her office, located 4 miles west and 4 miles south of the courthouse. find the distance between the lawyer s home and her office.

Alawyer drives from her home, located 1 mile east

purplefish53

13.03.2022

d = 13 miles

Explanation:

Lets say the position of court house is origin in this case

her office is located at 4 miles west and 4 miles south of court house

so here we have coordinate of the office with respect to court house is given as

$r_1 = (-4\hat i - 4\hat j)$

now the position of her home is located at 1 miles east and 8 miles north of the court house

so the coordinates of her home is given as

$r_2 = (1\hat i + 8 \hat j)$

now the change in the position is given as the distance between office and home

d = r_2 - r_1

$d = 5 \hat i + 12 \hat j$

$d = \sqrt{5^2 + 12^2} = 13 miles$

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michael4443

08.02.2020

The trip was 434mph quicker.

Explanation:

Time taken for case 1 = distance/ time = 2000/400= 5hrs

Time taken in case 2 = distance / time = 2000/480= 4.2hrs

Time taken for the entire journey = 5 + 4.2 = 9.2hrs

Total distance = 2000+ 2000= 4000miles

Total speed = total distance / total time

Total speed = 4000/9.2 =434.78mph

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