![Madisonaubrey22](/avatars/22861.jpg)
Madisonaubrey22
22.10.2019 •
Physics
Along solenoid of length 9.10 × 10-2 m and cross-sectional area 5.0 × 10-5 m2 contains 6500 turns per meter of length. determine the magnitude of the emf induced in the solenoid when the current in the solenoid changes from 0 to 1.5 a during the time interval from 0 to 0.20 s.
Solved
Show answers
More tips
- F Family and Home How to Remove Fading from Clothes: Tips and Tricks...
- F Family and Home How to Remove Tar Stains: Tips and Recommendations from Experts...
- L Leisure and Entertainment How to Learn to Draw Graffiti: Tips for Beginners...
- G Goods and services How to sew a ribbon: Tips for beginners...
- L Leisure and Entertainment How to Land on the Moon: Your Comprehensive Guide...
- H Health and Medicine Novomin: What is it and how to use it?...
- A Art and Culture Attention, the Final Episode of Margo is Almost Here!...
- A Art and Culture How to Learn Screaming: Step-by-Step Guide for Beginners...
- D Dating, Love, Relationships 10 Useful Tips on How to Survive a Breakup?...
- S Style and Beauty How to Break in New Shoes: 7 Simple Methods...
Answers on questions: Physics
- M Mathematics Solve the following pair of simultaneous equations using a graphical method: y=5-2x y=2x-7...
- P Physics Please help with these ASAP and plz explain so I can understand!!!...
- M Mathematics What is the domain of this function?...
- B Business Donnelley products sells 2,500 kayaks per year at a sales price of $470 per unit.donnelley sells in a highly competitive market and uses target pricing. the company has $1,000,000...
- M Mathematics Simplify 6 - (-2) - 31-5). -11 -7 19 23...
Ответ:
1.8 mV
Explanation:
The total number of turns in the solenoid is
where
n = 6500 is the number of turns per meter of length
The flux linkage through the solenoid is given by
where
B is the strength of the magnetic field
The strength of the field in the solenoid is given by
where I is the current.
At the beginning, I = 0, so the field is
And the flux linkage is
Later, the current is I = 1.5 A, so the field in the solenoid is
So, the flux linkage is
So, the change in flux linkage is
And therefore, the emf induced in the solenoid is (in magnitude)
Ответ:
Option A.
Explanation:
In order to create many magnetic field lines, stronger magnets are used so that the cutting of the magnetic field lines will be more frequent creating a higher magnetic induction.