Amarble column of cross-sectional area 1.6 m^2 supports a mass of 26600 kg. the elastic modulus for marble is 5.0 times 10^10 n/m^2. by how much is the column shortened if it is 7.9 m high? express your answer to two significant figures and include the appropriate units.

Δ L = 2.57 x 10⁻⁵ m

Explanation:

given,

cross sectional area = 1.6 m²

Mass of column = 26600 Kg

Elastic modulus, E = 5 x 10¹⁰ N/m²

height = 7.9 m

Weight of the column = 26600 x 9.8

                                    = 260680 N

we know,

Young's modulus=

stress =

           =

           = 162925

strain =

now,

   Δ L = 2.57 x 10⁻⁵ m

The column is shortened by Δ L = 2.57 x 10⁻⁵ m

Explanation:

An atomic model with negative charges located at a distance from central positive particles means that the negative charges are more exposed, on the outside of the atom, and, therefore, are more susceptible to being separated from the atom, while the positive particles that are inside the atom are more protected.

Thus, since the charged particles in the beams that Thomson studied moved away from their original atoms, you can imagine that those particles were, indeed, at a distance from the central positive particles, so they are easier to remove.