Amass of 0.40 kg, hanging from a spring with a spring constant of 80 n/m, is set into an up-and-down simple harmonic motion. what is the speed of the mass when moving through the equilibrium point? the starting displacement from equilibrium is 0.10 m.

v = 1.22 m/s

Explanation:

Given that,

Mass of the object, m = 0.4 kg

Spring constant of the spring, k = 80 N/m

The starting displacement from equilibrium is 0.10 m, or the amplitude, A = 0.1 m

To find,

The speed of the mass when moving through the equilibrium point.

Displacement in the mass, y = 0.05

Solution,

Let is the angular frequency of the mass. It can be calculated as :

When the mass displaces from some position, the speed of the mass is given by :

v = 1.22 m/s

So, the speed of the mass when moving through the equilibrium point is 1.22 m/s.

The resistance of the lamp when it is plugged into a standard wall outlet is 240 Ohms.

Given the following data:

Note: In the United States of America, a standard wall outlet supplies a voltage of 120 Volts.

To determine the resistance of the lamp when it is plugged into a standard wall outlet, we would apply Ohm's law:

Ohm's law states that at constant temperature, the current flowing through an electrical circuit is directly proportional to the voltage (potential difference) applied across its terminals and inversely proportional to the resistance in the electrical circuit.

Mathematically, Ohm's law is given by the formula;

Where;

Making R the subject of formula, we have:

Substituting the given parameters into the formula, we have;

Resistance, R = 240 Ohms

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