Amodel rocket rises from rest with constant acceleration of 106m/s2.what is the rocket speed at a height of 3.2m

At a height of 3.2 meters, the final speed of the model rocket is 26.05 m/s.

Given the following data:

Initial speed = 0 m/s (since the model rocket accelerated from rest).Acceleration = 106 Distance (height) = 3.2 meters.

To find the final speed of the model rocket, we would use the third equation of motion;

Where:

V is the final speed.U is the initial speed.a is the acceleration.S is the displacement or distance covered.

Substituting the given parameters into the formula, we have;

Final velocity, V = 26.05 m/s

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We can solve the problem by using the following equation:

where

vf is the final speed of the rocket

vi=0 is the initial speed of the rocket (it starts from rest)

is the rocket's acceleration

S=3.2 m is the distance covered by the rocket

Re-arranging the equation, we find the velocity of the rocket after 3.2 m:

time it with a stopwatch

Explanation: I have answered the same  question before