Amoving object has a mass of 2,000 kg and a speed of 10 m/s. a force of 5,000 n is applied. what is the distance it takes to stop?

Explanation:

m= 2000 kg

u= 10 m/s

v=0

f= 5000 N

a= f/m=-5000/2000=2.5 m/s^2

2 as= v^2-u^2

2*-2.5*s=0-100

         s=20 m

9514 1404 393

Step-by-step explanation:

Looking at the numbers individually, we have ...

16 = 4×4

42 = 2×3×7

6 = 2×3

17 = 1×17 (prime)

12 = 3×4

49 = 7×7

24 = 2×3×4

7 = 1×7 (prime, a multiple of 7)

11 = 1×11 (prime)

8 = 2×4

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Multiples of 4:

  16, 12, 24, 8

Multiples of 7:

  42, 49, 7

Multiples of neither:

  6, 17, 11