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zhellyyyyy
06.07.2019 •
Physics
An 80.0-kg object is falling and experiences a drag force due to air resistance. the magnitude of this drag force depends on its speed, v, and obeys the equation fdrag=(12.0n⋅s/m)v+(4.00n⋅s2/m2)v2. what is the terminal speed of this object?
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Ответ:
Terminal velocity of object = 12.58 m/s
Explanation:
We know that the terminal velocity is attained when drag force and gravitational force are of the same magnitude.
Gravitational force = mg = 80 * 9.8 = 784 N
Drag force =![12.0v+4.00v^2](/tpl/images/0057/9865/c77be.png)
Equating both, we have
So v = 12.58 m/s or v = -15.58 m/s ( not possible)
So terminal velocity of object = 12.58 m/s
Ответ:
A
Explanation: