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maelonramirez
16.07.2019 •
Physics
An airplane is flying at an elevation of 5150 ft, directly above a straight highway. two motorists are driving cars on the highway on opposite sides of the plane. the angle of depression to one car is 32°, and that to the other is 51°. how far apart are the cars? (round your answer to the nearest foot.) ft
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Ответ:
For the first car; The distance from the point on the highway below the plane
tan = opp/adj
tan(36°) = 5150/x
0.727 = 5150/x
0.727x = 5150
x = 7088.37
For the second car we also use tangent; the distance from the point on the highway below the plane will be;
tan(56°) = 5150/y
1.483 = 5150/y
1.483y = 5150
y= 3473.72
The we can add the two distances to get how far apart the cars are;
7088.37 + 3473.72 = 10562.09 feet.
= 10562.09 ft
Ответ:
Explanation:
the range of wavelengths or frequencies over which electromagnetic radiation extends.
This is know as elecromagnetic spectrum