Physics: An astronaut goes out for a space-walk at a distance above the earth equal to twice the radius of the earth. What is her acceleration due to gravity?

An astronaut goes out for a space-walk at a distance

Ответ:

jaelynnm

27.01.2022

Physics

Acceleration due to gravity will be $a=2.45 m/s^{2}$ .

Explanation:

We can use the gravitational force equation:

$F_{g}=G\frac{mM_{e}}{R^{2}}$

The F is equal to the weight of the astronaut, so we will have:

$ma=G\frac{mM_{e}}{R^{2}}$

$a=G\frac{M_{e}}{R^{2}}$

M(e) is the mass of the earth $M_{e}=5.972*10^{24}kg$ R is the radius of the earth $R=6.377*10^{6}m$ G is the gravitational constant $G=6.67*10^{-11}m^{3}kg^{-1}s^{-2}$

But the distance between the astronaut and the center of the earth is 2R, then we have:

$a=6.67*10^{-11}\frac{5.972*10^{24}}{(2*6.377*10^{6})^{2}}$

Therefore the acceleration due to gravity will be $a=2.45 m/s^{2}$ .

I hope it helps you!

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Ответ:

brianna5626

14.04.2020

Physics

The answer is 1.5m

Explanation:

Using the formula, V = f×λ to find the wavelength. Then sybstitute the following values into the equation :

f = 22Hz

V = 33m/s

33 = 22×λ

λ = 33/22

= 3/2

= 1.5m

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An astronaut goes out for a "space-walk" at a distance above the earth equal to twice the radius of the earth. What is her acceleration due to gravity?

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