Physics: An astronaut landed on a far away planet that has a sea of water. to determine the gravitational acceleration on the planet s surface, the astronaut lowered a pressure gauge into the sea to a depth of 24.3 m. if the gauge pressure is measured to be 3.8 atm, what is the gravitational acceleration on the planet s surface?

An astronaut landed on a far away planet that - id4139547, sierravick123owr441

deduran

12.01.2022

Acceleration due to gravity will be g=17.3m/sec^2

Explanation:

We have given gauge pressure P = 3.8 atm = 3.8×101325 = 385035 Pa

Depth h = 24.3 m

Density $\rho =1000kg/m^3$

We have find the acceleration due to gravity at the surface of planet

We know that pressure is given by

$P=\rho gh$

So $385035=1000\times g\times 24.3$

g=17.3m/sec^2

Acceleration due to gravity will be g=17.3m/sec^2

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LEXIEXO

09.02.2022

Thanks

Explanation:

thanks

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