![QuestionsAnsweredNow](/avatars/28888.jpg)
QuestionsAnsweredNow
28.01.2020 •
Physics
An astronaut notices that a pendulum which took 2.45 s for a complete cycle of swing when the rocket was waiting on the launch pad takes 1.25 s for the same cycle of swing during liftoff.
what is the acceleration (m/s²) of the rocket? (hint: inside the rocket, it appears that g has increased.)
Solved
Show answers
More tips
- F Family and Home How to Raise a Genius? Discover the Secrets Here...
- F Food and Cooking How to Properly Cook Buckwheat?...
- H Health and Medicine How to Tan in a Tanning Bed? Tips and Recommendations...
- S Style and Beauty How to Sew a Balloon Skirt: Detailed Tutorial and Tips on Choosing the Right Fabric...
- P Philosophy Personal attitude towards Confession: how to prepare and undergo the procedure correctly?...
- F Food and Cooking How to Make Cottage Cheese at Home: Simple and Quick Recipe with Step By Step Instructions...
- H Health and Medicine Which Water Are You Drinking? Is it Worth Buying Bottled Water?...
- H Health and Medicine What Makes a Man a Man?...
- H Health and Medicine What to Take with You to the Maternity Hospital?...
- F Food and Cooking What Foods Can Nursing Moms Eat?...
Answers on questions: Physics
- B Business You own a business and have decided you need an email policy 10 you three most important factors you would like your employees to understand about using their business email...
- M Mathematics Which equation could be used to solve the systems of equations using substitution? y=-3 - X y = 3x + 5 A.) 3x - x = -3 + 5 B.)-3 - X = 3x + 5 C.)-3 - y = 3y + 5 D.)y = 3x...
- B Biology What type of mutation occurs when one base replaces another base in a dna codon?...
- E English Question 3 In Paragraph 1, MLK, Jr. says that he is writing this letter from jail to answer them in what he hopes will be and terms. List the two words that fill in the...
Ответ:
2.84 g's with the remaining 1 g coming from gravity (3.84 g's)
Explanation:
period of oscillation while waiting (T1) = 2.45 s
period of oscillation at liftoff (T2) = 1.25 s
period of a pendulum (T) =2π.![\sqrt{\frac{L}{a} }](/tpl/images/0479/1732/9347f.png)
where
L = lengtha = accelerationtherefore the ration of the periods while on ground and at take off will be
where
a1 = acceleration on ground while waitinga2 = acceleration during liftoffsquaring both sides we have
assuming that the acceleration on ground a1 = 9.8 m/s^{2}
a2 = 9.8 x![(\frac{T1}{T2})^{2}](/tpl/images/0479/1732/39176.png)
substituting the values of T1 and T2 into the above we have
a2 = 9.8 x![(\frac{2.45}{1.25})^{2}](/tpl/images/0479/1732/8a87f.png)
a2 = 9.8 x 3.84
take note that 1 g = 9.8 m/s^{2} therefore the above becomes
a2 = 3.84 g's
Hence assuming the rock is still close to the ground during lift off, the acceleration of the rocket would be 2.84 g's with the remaining 1 g coming from gravity.
Ответ:
For him being such a fat bear, it would have taken alot of work
Explanation: