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Blackhawk1881
14.04.2020 •
Physics
An electron and a second particle both move in circles perpendicular to a uniformmagnetic field. The mass of the second particle is the same as that of a proton but thecharge of this particle is different from that of a proton. If both of time to go once around their respective circles, determine the charge of thissecond particle. You may use the values:melectron9.1110−31kg,qelectron1.6010−19C, andmproton1.6710−27kg.
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Ответ:
The change on the second particle is
.
Explanation:
The period of revolution of the particle in the magnetic field is given by the formula as follows :
It is given that the magnetic field is uniform. The mass of the second particle is the same as that of a proton but thecharge of this particle is different from that of a proton.
If both particles take the same amount of time to go once around their respective circles. So,
So, the change on the second particle is
.
Ответ:
a) ω=n
b) V = R*n
c) a = 0
d)![ar = R*n^2](/tpl/images/0374/8327/00a13.png)
Explanation:
Angular velocity is given by the derivative of θ:
ω = n
Linear Velocity will be:
V = ω*R = n*R
Tangential acceleration will be the derivative of the linear velocity. Since velovity is constant:
a = 0
Radial acceleration is given by: