An experiment was performed on a 2-kg block. forces of 5, 10 and 15 newtons respectively were applied to the block for 5 seconds. describe the difference in final speed between the three trials.

From Newton's second law of motion, 
                                     F = ma = mv/t
Where F is force, m is mass, a is acceleration, v is velocity, and t is time. Substituting the known values from the given,
   (a)          5 N = (2 kg)(v)/(5 s)    ;     v = 12.5 m/s
    (b)        10 N = (2 kg)(v) /(5 s)  ;     v = 25 m/s
   (c)          15 N = (2 kg)(v) /(5s)  ;      v = 37.5 m/s

Therefore, the greater the amount of force, the higher is the final velocity of the block. 

3.57N

Explanation:

given

Speed of rotation, N = 1300 rpm

diameter, d = 35 cm, so that

radius, r = 17.5 cm = 0.175 m

mass of drop = 1.1 g = 1.1*10^-3 kg

Angular speed of water, ω = 2πN/60

ω = 2π*1300/60

ω = 8169.2/60

ω = 136.15 rad/s

apparent weight will be gotten by

W(a) = mω²r

W(a) = 1.1*10^-3 * 136.15² * 0.175

W(a) = 1.1*10^-3 * 18536.82 * 0.175

W(a) = 3.57 N

Therefore, the apparent weight of 1.1 g of water is 3.57 N