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destinee71
02.01.2021 •
Physics
An ideal spring with spring constant k is hung from the ceiling. The initial length of the spring, with nothing attached to the free end, is 15.0 cm. When an object of mass m is attached to the free end of the spring, the spring stretches to a final length of 30.0 cm. If k = 3.5 N/cm, what is the mass m of the object?
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Ответ:
The mass m of the object = 5.25 kg
Further explanationGiven
k = spring constant = 3.5 N/cm
Δx= 30 cm - 15 cm = 15 cm
Required
the mass m
Solution
F=m.g
Hooke's Law
F = k.Δx
Ответ:
Explanation:
The distance between successive wave crests at sea is 20 m. The boat descends from the crest of the wave, rises and reaches the highest position again within 5 s. Calculate the wave propagation speed.
Given that,
The distance between two successive crest is 20m
Wavelength is the distance between two successive crest or trough
Then, it's wavelength is λ = 20m
The time to reached the maximum height is 5seconds, then it will take (5×4) to complete one period
Then,
Period T = 20seconds
From wave equation
v = fλ
Where
v is speed
f is frequency and
λ is wavelength
The frequency is related to the period
f = 1 / T
Then,
v = λ / T
So, v = 20 / 20
v = 1 m/s
The speed of propagation of the wave is 1m/s
To Polish
Jeśli się uwzględni,
Odległość między dwoma kolejnymi grzebieniami wynosi 20 m
Długość fali to odległość między dwoma kolejnymi grzebieniami lub dolinami
Zatem jego długość fali wynosi λ = 20 m
Czas do osiągnięcia maksymalnej wysokości wynosi 5 sekund, a następnie ukończenie jednego okresu zajmie (5 × 4)
Następnie,
Okres T = 20 sekund
Z równania falowego
v = fλ
Gdzie
v to prędkość
f oznacza częstotliwość, a
λ jest długością fali
Częstotliwość jest związana z okresem
f = 1 / T
Następnie,
v = λ / T
Zatem v = 20/20
v = 1 m / s
Prędkość propagacji fali wynosi 1m/s