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KaylaMaria
30.10.2020 •
Physics
An object is moving with an initial velocity of 5.5 m/s. It is then subject to an acceleration of 2.5 m/s² for 11 s. How far will it have traveled during the time of its acceleration? OML HELP
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Ответ:
211.75m
Explanation:
Listing everything the question gives you:
Vi = 5.5
a = 2.5
t = 11
ΔX = ?
Then pick a kinematic equation to solve for the missing variable
I used this one: Δx = Vit +![\frac{1}{2} at^2](/tpl/images/0854/0834/506f1.png)
When you plug in all ur variables you get Δx = 211.75m
Ответ:
bruv like actually tho
Explanation: