An object is placed in front of a diverging lens, such that the object-to-image distance is 71 cm.
find the focal length of the lens, if the image is 26 cm from the lens. the image is real.
a virtual object lies 95 cm in front of a diverging lens, with a 29 cm focal length.
find the location of the image.
find the magnification
is the image real or virtual?
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Ответ:
Explanation:
Given that,
Object-to-image distance d= 71 cm
Image distance = 26 cm
We need to calculate the object distance
We need to calculate the focal length
Using formula of lens
put the value into the formula
The focal length of the lens is 35.52.
(B). Given that,
Object distance = 95 cm
Focal length = 29 cm
We need to calculate the distance of the image
Using formula of lens
Put the value in to the formula
We need to calculate the magnification
Using formula of magnification
The magnification is 0.233.
The image is virtual.
Hence, This is the required solution.
Ответ:
a force is any interaction that, when unopposed, will change the motion of an object. A force can cause an object with mass to change its velocity, i.e., to accelerate. Force can also be described intuitively as a push or a pull. A force has both magnitude and direction, making it a vector quantity. Wikipedia
In SI base units: kg·m/s2
Other units: dyne, pound-force, poundal, kip, kilopond
Derivations from other quantities: F = m a
SI unit: Newton
Explanation:
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