An object is projected from the ground with an upward speed of ų m/s has a speed of 23m/s when it is at a height of 5m above the ground .Use work energy principle to determine the initial speed u.
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Ответ:
25.08m/s
Explanation:
mgh1 + 0.5mv1² = mgh2 + 0.5mv2²
h1 = 0m
v1 = u
h2 = 5m
v2 = 23m/s
putting the values into the formula above;
m(10)(0) + 0.5m(u²) = m(10)(5) + 0.5m(23²)
0 + 0.5mu² = 50m + 264.5m
0.5mu² = 314.5m
dividing through by m
0.5u² = 314.5
u² = 629
u = 25.08m/s
Therefore, the initial speed "u" = 25m/s
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