Physics: Aradioactive element x with atomic number 88 and mass number 226 emits in succession: 1)alpha particle 2)a beta particle 3)gamma radiation explain using equations where necessary te changes that take place in the atomic structure of the element at each stage

Aradioactive element x with atomic number 88 and - id884847135, punkinrichard1oxon2i

Marisolv06

20.06.2020

1) alpha particle, the element Radium undergoes alpha decay, releasing an alpha particle.

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eeeeee7891

11.05.2023

The correct answer is 0.022

Divide the volume value by 1000

22 divided by 1,000 = 0.022

Explanation:

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