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only1kariyah
05.09.2019 •
Physics
As a rain storm passes through a region, there is an associated drop in atmospheric pressure. if the height of a mercury barometer drops by 21.6 mm from the normal height, what is the atmospheric pressure (in pa)? normal atmospheric pressure is 1.013 ✕ 105 pa and the density of mercury is 13.6 g/cm3.
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Ответ:
new atmospheric pressure is 0.9838 ×
Pa
Explanation:
given data
height = 21.6 mm = 0.0216 m
Normal atmospheric pressure = 1.013 ✕ 10^5 Pa
density of mercury = 13.6 g/cm³
to find out
atmospheric pressure
solution
we find first height of mercury when normal pressure that is
pressure p = ρ×g×h
put here value
1.013 ×
= 13.6 × 10³ × 9.81 × h
h = 0.759 m
so change in height Δh = 0.759 - 0.0216
new height H = 0.7374 m
so new pressure = ρ×g×H
put here value
new pressure = 13.6 × 10³ × 9.81 × 0.7374
atmospheric pressure = 98380.9584
so new atmospheric pressure is 0.9838 ×
Pa
Ответ:
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