Physics: As new-forming stars grow by gravitationally attracting more material, they become brighter. If a star becomes too bright, the radiation pressure from the star prevents gravity from pulling in more material. What power output PP would a star with a mass 35.135.1 times that of our Sun need to have in order to be unable to pull in a 3.96 μg3.96 μg dust particle of radius rp=0.935 mm,rp=0.935 mm, assuming the particle absorbs all the light incident on its πr2pπrp2 cross‑section? The mass ⊙M⊙ of the

As new-forming stars grow by gravitationally attracting

Teddybearnerd

25.01.2022

The power output of the star is 2.215x10²⁸W

Explanation:

Given data:

ms = mass of the star = 35.135 times msun

rp = radius = 0.935 mm = 9.35x10⁻⁴m

p = 3.46 μg = 3.46x10⁻⁹g

msun = mass of the Sun = 1.99x10³⁰kg

G = gravitational constant = 6.67x10⁻¹¹m³/kg s²

c = speed of light = 3x10⁸m/s

Question: What power ouput would a star, P = ?

First, calculate the mass of the star:

$m_{s} =35.135*1.99x10^{30} =6.992x10^{31}kg$

The power output of the star:

$P=\frac{Gm_{s}*p*4c }{r^{2} } =\frac{6.67x10^{-11}*6.992x10^{31}*3.46x10^{-9}*4*3x10^{8}}{(9.35x10^{-4})^{2} } =2.215x10^{28}W$

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