As phase change occurs the freedom of the motion of the particles increase

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Ответ:

FloweyFlower

20.05.2021

Physics

The gauge pressure of the air in the tires is 179.5 kPa.

Solution :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

P_1 = initial pressure of gas = Atmospheric pressure + gauge pressure = 101 kPa + 165 kPa = 266 kPa

P_2 = final pressure of gas = ?

V_1 = initial volume of gas = $1.63\times 10^{-2}m^3$

V_2 = final volume of gas = $1.70\times 10^{-2}m^3$

T_1 = initial temperature of gas = 0^oC=273+0=273K

T_2 = final temperature of gas = 27.3^oC=273+27.3=300.3K

Now put all the given values in the above equation, we get the final pressure of gas.

$\frac{266\times 1.63\times 10^{-2}}{273K}=\frac{P_2\times 1.70\times 10^{-2}}{300.3K}$

P_2=280.5kPa

Gauge pressure = Absolute pressure - atmospheric pressure = (280.5 - 101) kPa= 179.5 kPa

Therefore, the gauge pressure of the air in the tires is 179.5 kPa.

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