Asealed cylinder contains a sample of ideal gas at a pressure of 2.0 atm. the rms speed of the molecules is v0. if the rms speed is then reduced to 0.90 v0, what is the pressure of the gas?

The pressure of the gas is 1.8 atm.

Explanation:

Given that,

Pressure of ideal gas= 2.0 atm

rms speed of the molecule = v₀

Reduced rms speed = 0.90 v₀

We know the formula of rms speed of the ideal gas

From this formula rms speed is directly proportional to square root is pressure.

We need to calculate the pressure of the gas

Using formula of rms speed

Put the value into the formula

Hence, The pressure of the gas is 1.8 atm.

The instantaneous velocity of the object when t = 4.1 is 9.7 .

Explanation:

Instantaneous velocity, v =

x =

v = = 2bt - c

At t = 4.1 s

v = 2 × b × 4.1 - c

b = 2.0

c = 6.7 ...(Given)

v = 2 × 2 × 4.1 - 6.7

v = 9.7

The instantaneous velocity of the object when t = 4.1 is 9.7 .