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khalilh1206
24.07.2019 •
Physics
Aseries circuit consists of a 0.55-h inductor with internal resistance of 8.0 ω connected in series with a 4.0-ω resistor, an open switch, and an ideal 12-v battery. (a) when the switch is closed, what is the initial current through the 4.0-ω resistor? (b) what is the current through the 4.0-ω resistor a very long time after the switch is closed?
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Ответ:
Part a)
i = 0
Part b)
i = 1 A
Explanation:
Part a)
As per Lenz law we know that inductor in series circuit opposes the sudden change in current
And if the flux in the circuit will change then it will induce back EMF to induce opposite current in it
Now when we close the switch at t = 0
then initially it will induce the opposite EMF in such a way that net EMF of the circuit will be ZERO
so current = 0
Part b)
After long time the induced EMF in the circuit will be zero as the flux will become constant
so here we can say
Ответ: