Physics: Ashopper pushes a cart 29 m south down one aisle and then turns 90.0° west and moves 29 m. he then makes another 90.0° turn and moves 14 m. (a) what is the largest possible displacement of the shopper?

Ashopper pushes a cart 29 m south down one aisle

aaaranda0308

08.01.2022

d = 51.86 m

Explanation:

For largest possible displacement we can say that it must move towards south after it turns 90 degree at the end

So we will have

x_1 = 29 m South

y_1 = 29 m West

x_2 = 14 m South

so total displacement towards South

x = x_1 + x_2 = 29 + 14

x = 43 m

so net maximum displacement will be

$d = \sqrt{x^2 + y^2}$

$d = \sqrt{43^2 + 29^2}$

d = 51.86 m

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kyliech023

15.07.2021

KN= 15 units

NM= 20 units

Step-by-step explanation:

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