Askier traveling 11.0 m/s reaches the foot of a steady upward 17 â incline and glides 15 m up along this slope before coming to rest. part a what was the average coefficient of friction?

The attached free-body diagram shows the forces that are responsible for the skier coming to rest eventually on the incline.

We see that the component of his Weight along the incline and the Friction both act in tandem to stop him.

In order to calculate the Friction, we can make use of Newton's 2nd law, which states that

The here is given by , where is the Kinetic Friction.

We also know that the magnitude of Friction Force can be calculated using the equation μ., where is the Normal Force acting perpendicular to the incline as shown in the figure.

We see that since they both balance each other out.

Hence, putting all these together, we have μ.

Simplifying this, we get μ

We clearly see that we need to calculate the acceleration before we can obtain the value of the Coefficient of Friction μ

And for that, we make use of the following data obtained from the question:

Initial Velocity

Final Velocity

Displacement along the incline

Acceleration a = ?

Using the equation , and

Plugging in known numerical values, we get

Solving for a gives us,

Since the negative sign indicates that this is deceleration, we can ignore the sign and consider the magnitude alone.

Thus, plugging in in the force equation we wrote above, we have

μ.

Solving this for μ, we get its value as μ = 0.124

Thus, the average coefficient of friction on the incline is 0.12

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