Asmall block of mass m1 is released from rest at the top of a curve-shaped, frictionless wedge which sits on a frictionless horizontal surface. the height of the wedge is h=5m. when the block leaves the wedge its velocity relative to the ground is measured to be 4 m/s to the right. if the mass of the block is doubled to become 2m1 what, what will its speed be when it leaves the wedge?
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Ответ:
put equation 3. into 1. together with h = 5:
4.
when I double m₁ the ratio becomes:
5.
when I put these to ratios back into equation nr 1 and nr2, I find the ratio:
and new v₁ = 2.95
I'm not sure this is correct.
Ответ:
D. There are infinitely many solutions since -5=-5 is a true statement.
Step-by-step explanation:
7x-5+5x=15x-7-3x+2.
12x-5=12x-5
-5=-5
This is always true so there are infinite solutions