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Kennedy3449
16.10.2019 •
Physics
Asmall lead ball, attached to a 1.5-m rope, is being whirled in a circle that lies in the vertical plane. the ball is whirled at a constant rate of three revolutions per second and is released on the upward part of the circular motion when it is 0.75 m above the ground. the ball travels straight upward. in the absence of air resistance, to what maximum height above the ground does the ball rise?
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Ответ:
H=10.93 m
Explanation:
Given that
h'= 0.75 m
r= 1.5 m
ω = 3 rev/s
ω = 3 ₓ 2 π rad/s
ω = 6 π rad/s
Speed of the ball when it releases from the rope,V.
V= ω x r
V= 6 π x 0.75
V=14.13 m/s
We know that acceleration due to gravity always in downward direction.
The final speed will be zero
h = 10.18 m
So the height from the ground,H = h' + h
H= 10.18 + 0.75 m =10.93 m
H=10.93 m
Ответ:
Latitude- Vertical (North South)