Aspring is stretched from x=0 to x=d, where x=0 is the equilibrium position of the spring. it is then compressed from x=0 to x=−d. what can be said about the energy required to stretch or compress the spring? view available hint(s) a spring is stretched from to , where is the equilibrium position of the spring. it is then compressed from to . what can be said about the energy required to stretch or compress the spring? more energy is required to stretch the spring than to compress it. the same amount of energy is required to either stretch or compress the spring. less energy is required to stretch the spring than to compress it.

The same amount of energy is required to either stretch or compress the spring.

Explanation:

The amount of energy required to stretch or compress a spring is equal to the elastic potential energy stored by the spring:

where

k is the spring constant

is the stretch/compression of the spring

In the first case, the spring is stretched from x=0 to x=d, so

and the amount of energy required is

In the second case, the spring is compressed from x=0 to x=-d, so

and the amount of energy required is

so we see that the amount of energy required is the same.

I think I have the answer to your problem!!

A pot of boiling water is a nice everyday example to explain internal energy, heat, and work. However, it's not a good choice for applying the first law of thermodynamics, because the boiling pot isn't a closed system.

Explanation:

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