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madisongibson714
04.03.2020 •
Physics
Assume that charge −q−q-q is placed on the top plate, and +q+q+q is placed on the bottom plate. What is the magnitude of the electric field EEE between the plates?
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Ответ:
Magnitude of electric field = E = q/Aε0
Explanation:
Consider plates are placed at a distance of d. As given in the question the charge stored on the plates have magnitude q and given by:
q = CV
And
V = q/C ……. (i)
The capacitance is given by the following equation:
C = Aε0/d ……. (ii)
Put equation (ii) in (i) ,
V = qd/ Aε0 …..(iii)
The electric field is defined as:
E = V/d …… (iv)
Put equation (iii) in (iv),
E = qd/ Aε0d
E = q/Aε0
Hence, the magnitude of electric field will be q/Aε0 .
Ответ:
combustion reaction im pretty sure
Explanation: