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bommers144
15.12.2020 •
Physics
Assume the mass of a shuttlecraft is 2,200 kilograms [kg]. If the shuttlecraft requires 3 minutes [min] to rise from the surface of the Moon to an altitude of 19 kilometers [km], and the shuttle's engine is rated at 500 kilowatts [kW], what is the efficiency of the engines
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Ответ:
The efficiency of the engine is 75.94 %
Explanation:
Given;
mass of the shuttlecraft, m = 2,200 Kg
time required by the shuttlecraft, t = 3 minutes = 180 s
height risen by the shuttle, h = 19 km = 19,000 m
Input power of the shuttle, Pi = 500 kW = 500,000 W
The potential energy due to height risen by the Shuttle on Moon surface is given as;
E = mgh
where;
g is the acceleration due to gravity on moon, = ¹/₆ x 9.81 m/s² = 1.635 m/s²
E = 2200 x 1.635 x 19,000
E = 68343000 J
Output power of the shuttle, is given as Energy / time
Output power = (68343000) / (180)
Output power = 379,683.33 W
The efficiency of the shuttle is given as;
Efficiency = (Output power) / (Input power)
Efficiency = (379,683.33) / (500,000)
Efficiency = 0.7594
Efficiency(%) = 75.94 %
Therefore, the efficiency of the engine is 75.94 %
Ответ: