Assume: The system shown below starts from rest and there are no frictional forces opposing the motion of the system. The dolly and its wheels have negligible mass. The acceleration of gravity is 9.8 m/s2. 28.8 N 350 N If a person pulls on the rope with a constant force what is the acceleration of the system: Answer in units of m/s-

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Explanation:

28.7 m at 46.9°

Explanation:

The x component of the displacement is:

x = 6 m cos 0° + 25 m cos 57°

x = 19.6 m

The y component of the displacement is:

y = 6 m sin 0° + 25 m sin 57°

y = 21.0 m

The total displacement is found with Pythagorean theorem:

d = √(x² + y²)

d = 28.7 m

And the direction is found with trig:

θ = tan⁻¹(y/x)

θ = 46.9°