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Rodriguezi4971
05.10.2019 •
Physics
Astone thrown off a bridge 10m above a river has an initial velocity of 8ms at an angle of 25 degrees above the horizontal. what is the range of the stone?
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Ответ:
Explanation:
It is given that,
Height above which the stone was thrown, h = 10 m
Initial velocity of the stone, u = 8 m/s
Angle above the horizontal,![\theta=25^{\circ}](/tpl/images/0288/1857/3d6ac.png)
The horizontal component of velocity is,![u_x=v\ cos\theta=8\ cos(25)=7.25\ m/s](/tpl/images/0288/1857/ef342.png)
The vertical component of velocity is,![u_y=v\ sin\theta=8\ cos(25)=3.38\ m/s](/tpl/images/0288/1857/6598a.png)
Let t is the time of flight in vertical motion. The second equation of motion is :
t = 0.34 seconds
Let s is the range of the stone. It can be calculated as :
s = 2.46 meters
So, the range of the stone is 2.46 meters. Hence, this is the required solution.
Ответ: