Astudent drops a rock from a bridge to the
water 12 m below.
with what speed does the rock strike
the water?
answer in units of m/s
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Ответ:
15.49m/s
Explanation:
Using one of the equations of motion;
Where;
v = the final velocity of the rock.
=> This is the speed at which the rock strikes the water.
u = initial velocity of the rock.
=> The rock is just dropped from that height. That means the initial velocity is zero (0).
=> u = 0
g = the acceleration due to gravity.
=> Since the rock moves downwards, the acceleration due to gravity is positive and let it have a value of 10m/![s^{2}](/tpl/images/0481/8110/c60b2.png)
=> g = 10m/![s^{2}](/tpl/images/0481/8110/c60b2.png)
s = the distance covered by the rock
=> s = 12m
Substituting these values into the equation above gives
v =![\sqrt{240}](/tpl/images/0481/8110/99232.png)
v = 15.49m/s
Therefore the velocity(speed) with the rock strikes the water is 15.49m/s
Ответ:
hope that will help you